in the adjacent diagram ,if n(u)=125 two times of x and z is 10 more than x, then find the value of x,y,and z
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Answer:
⇒n(0)=125
⇒y=2x(given)→(i)
⇒z=x+10(given)→(ii)
Then,A/qtodiagram
⇒x+4+3+6+y+3+4+17+6+3+17+z=125
fromequation(i),(ii)and(iii)
⇒x+y+z=125−63
⇒x+2x+x+10=62
⇒4x=52
x=13
∴y=2x=2×13=26
∴z=x+10=23
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