in the adjacent figure, AB//CD. Determine _|_ a
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Answer:
let angle ABQ = 38° and angle CDQ=35° and a=X
by question we get,
angle ABQ+angle CDQ+X =180°( straight line)
38°+35+x°=180°
73°+x=180°
x=180°-73°
x=107°
therefore X=180°
hope it helps and if there's a mistake do correct me and forgive me...
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