Question

In the adjacent figure AB//CD, then find x value.​

Answer 1

Step-by-step explanation:

Given that AB∣∣CD

Taking PQ as transversal,

∠RQP=∠QPC=80∘

Now,

∠QPC+2x+3x=180∘

80∘ +5x=180∘

5x=130∘

x=26∘

now, applying angle sum property in triangle PQR,

2x+y+∠PQR=180∘

2×26+80∘ +y=180∘

y=48∘

now,

z=2x+80∘

(An exterior angle of a triangle is equal to the sum of the opposite interior angles)

z=2×26∘ +80∘ =52∘ +80∘ =132∘

z=132∘

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Answer 2

Step-by-step explanation:

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