Question

in the adjacent figure ab is a chord of circle with centre o.cd is the diameter perpendicular to ab. show that ad=bd​

Answer 1

Answer:

Let D meet AB at P

In∆DPA and ∆DPB

AP=PB [ perpendicular drawn to the chord bisects the chord]

DP=DP [common side]

angle DPA= angle DPB [Both are equal to 90°]

By Side Angle Side , ∆DPA = ∆DPB

By CPCTC AD = BD

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