in the adjacent figure ABCD is a parallelogram and AbeF is a rectangle show that triangle Afd congruent to triangle Bec
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Answer:In triangle ACE and triangleBDF:-
AC=BD(opposite sides of a parralalogram)
AE=BF(opposite sides of a rectangle)
AngleACD=90degree(each angle of rectangle is 90degree)
AngleBDC=90(same reason as above)
And angleBDC+angleBDF=180(l.p)
90+angleBDF=180
AngleBDF=90
AngleBDF=angleACD(each 90degree)
TriangleACEcongruent triangleBDF(byRHS)
Step-by-step explanation:
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