Question

in the adjacent figure, ABCD is a parallelogram and line segment AE and CF bisect the angle A and C respectively. show that a A parallel to CF .

Answer 1

Given,

ABCD is a ||gm , linesegment AE and CF bisects <A and <C .

To proof,

AE || CF

Proof,

(1) <A = <C

=> 1/2 <A = 1/2 <C

=> <1 = <2

(2) AB||CD and CY is the transversal

So, <2=<3.

From equation (1) and (2) we have ,

=> <1 = <2

Transversal AB intersect AE and CF at A and F such that ,

=> <1 = <3

= AE||CF

Hence , proved !!

Answer 2

Answer:

Hope it helps you.....