In the adjacent figure, ABCD is a parallelogram, CE AB produced and BF AD
(a) If AD = 10cm, CE = 8cm, and BF = 12cm, find AB.
(b) If AB = 16cm, AD = 12cm and CE = 10cm, find BF.
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In the figure, ABCD is a parallelogram. If DE = 4 cm, then BF equals :
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⇒ In given figure ABCD is a parallelogram.
⇒ AB=DC=6cm and AD=BC=3cm ---(1) [Opposite sides of parallelogram are parallel and equal]
⇒ We can see in figure DE ⊥ AB
⇒ So, area of parallelogram ABCD with height DE and baseAB is,
⇒ Area of parallelogram ABCD =
2
1
×AB×DE
⇒
2
1
×6×4 [From ( 1 )]
∴ Area of parallelogram ABCD=12cm
2
----- ( 2 )
⇒ In figure BF⊥AD
⇒ So now we can take BF as a height and AD as a base.
⇒ Area of parallelogram ABCD=
2
1
×AD×BF
⇒ 12=
2
1
×3×BF [From ( 1 ) and ( 2 )]
⇒ BF=
3
24
∴ BF=8cm
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