. In the adjacent figure, ABCD is a
parallelogram. The measures of AB and
BC are 6 cm and 4 cm respectively.
If the measure of the height BF with
respect to the base AD is 4.9 cm. then
find the height DE of the parallelogram
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= Area of ABCD = b×h
=Area of ABCD = AD ×BF
= Area of ABCD = 4 cm × 4.9 cm
= Area of ABCD = 19.6 sq. cm
=. b × h = 19.6 sq. cm
= 6 cm × DE = 19.6
= DE = 19.6 ÷ 6
= DE = 3.2 cm
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