Question

In the adjacent figure, ABCD is a rectangle. If BM and DN are
perpendiculars from B and D on AC, prove that A BMC = ADNA. Is it
true that BM = DN?​

Answer 1

$\huge\boxed{\fcolorbox{yellow}{orange}{☞✿ANSWER:-}}$

In triangle BMC and triangle DNA

BC = AD ( opposite sides of rectangle are equal )

∠BCM = ∠MAD ( Alternate angles )

∠BCM = ∠DNA ( BM and DN are Perpendicular to AC )

Therefore,

By AAS Criterion Rule,

▲ BMC ≅ ▲ DNA

By CPCT,

BM = DN.

HENCE PROVED

Answer 2

Answer:

YES 0 IS THE ANSWER

Step-by-step explanation: