In the adjacent figure, ABCD is a rectangle. If BM and DN are perpendiculars from B and D on AC . Prove that ∆ABC =~ ∆DNA.
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In a triangles BMC and DNABC = DA (Opposite sides) ∠BCM = ∠DAN (alternate angles) ∠DNA = ∠BMC = 90° [DN and BM are perpendicular to AC] So by AAS Congruency criterion ΔBMC ≅ ΔDNA BM = DN (By CPCTRead more on Sarthaks.com - https://www.sarthaks.com/1132009/adjacent-figure-abcd-rectangle-and-perpendiculars-from-prove-thatbmcdna-true-that
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