In the adjacent figure, ABCD is a trapezium in which AB||DC. If angle A=60° and angle B=40° . Find the measure of its remaining two angle
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sum of two interior angle of transversal line is 180
so sum of A and D =180
60+x=180
x=120
D=120
and sum of B and C=180
40+x=180
x=140
so sum of A and D =180
60+x=180
x=120
D=120
and sum of B and C=180
40+x=180
x=140
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