Question

. In the adjacent figure, ABCDEF is a polygon in which AL = 10cm, AM = 20 cm, AN = 50 cm, AO = 60 cm and AD = 90 cm.Find the area of the polygon.(BLIAD, FM IAD, CNI AD and EO I AD)​

Answer 1

Answer:

where is the figure then we should tell the answer

Answer 2

Given:AL=10 cm, AM=20 cm, AN=50 cmAO=60 cm, AD=90 cmHence, we have the following:MO=AO-AM=60-20=40 cmOD=AD-AO=90-60=30 cmND=AD-AN=90-50=40 cmLN=AN-AL=50-10=40 cmFrom given figure:Area of Polygon=(Area of triangle AMF)+(Area of trapezium MOEF)+(Area of triangle EOD)+(Area of triangle DNC)+(Area of trapezium NLBC)+(Area of triangle ALB)=(12×AM×MF)+[12×(MF+OE)×(OM)]+(12×OD×OE)+(12×DN×NC)+[12×(LB+NC)×(NL)]+(12×AL×LB)=(12×20×20)+[12×(20+60)×(40)]+(12×30×60)+(12×40×40)+[12×(30+40)×(40)]+(12×10×30)=200+1600+900+800+1400+150=5050 cm2