Question

In the adjacent figure AE = AF, then
EXX VDE
a
ob
B
C​

Answer 1

Answer:

triangle DFB,

∠X=b−a & AE = AF

So, ∠X=∠Y=b−a

∠DEC=180°−a−c

180°−b+a=180°−a−c

2a+c=2b

2a+c=2b

Step-by-step explanation:

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