In the adjacent figure, Ao and ob are incident and
reflected rays respectively . AoB = 90° Find the
values of angle of reflection ?
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Answer:
45°
Explanation:
hopi it helps
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Explanation:
ON is normal on the plane mirror at point O
ON is perpendicular on a plane mirror
Angle of incidence ∠i = ∠AON and angle of reflection ∠r = ∠BON Since, ∠i – ∠r ∠AOB = 90° ⇒ ∠AON + ∠BON = 90° ⇒∠i + ∠i – 90° ⇒ 2 ∠i =90° ⇒ ∠i = 90 / 2 = 45°
∴Angle of incidence = ∠i = 45° and Angle of reflection ∠i = 45°
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