in the adjacent figure AOB is a straight line ∆AOD=120° ∆BOC=110° then find ∆COD
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∠AOB = 180° = ∠AOD+∠DOC+∠COB ( Linear Pair )
180° = (2x - 7) + (2x - 3) + (x - 10)
180° = 5x - 20
36° = x - 4
x = 40°
∠AOD = (2*40 - 7)° = (80 - 7)° = 73°
∠DOC = (2*40 - 3)° = (80 - 3)° = 77°
∠COB = (40 - 10)° = 30°
maratiakhilp252dq:
Lateral surface area = 4a squre
its just simple
apply the formula 6a*2
thanks
and a=10 cm
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