Question

in the adjacent figure AOB is a straight line find angle AOC and question b- angle BOC

Answer 1

★ Hey mate ★


here is your answer !!


x + 15 + 3x + 25 = 180 ° { straight line }


4x + 40°= 180°

=> 4x = 140 °


x = 35



hence , angle < AOC = x + 15

=> ★ 35 + 15 = 50 ★


and < BOC = 3× X + 25


=> ★ 130 ★



hope it helps you dear friend !!


$thanks$

Answer 2

It is given in the question that ∠ AOC = x+15°.
∠ BOC = 3x+25°.
∵ ∠ AOC and ∠ BOC forms a linear pair,
∴ ∠ AOC + ∠ BOC = 180°.
 ATQ,
x+15° + 3x+25° = 180°.
4x + 40° = 180°.
4x = 180° - 40°,
4x = 140°,
x = 35°.

Now,
Substituting the value of x to find the required angles.
∠ AOC = x+15° = 35+15 = 50 °.
                      and 
∠ BOC = 3x+25° = 3(35)+25 = 105+25 = 130°.

∴ The required angles are 50° and 130°