In the adjacent figure BE perpendicular DA and CD perpendicular DA then prove that m angle 1 =~m angle 3
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Answer:
∵ CD is perpendicular to DA and BE is perpendicular to DA
∴ ∠CDA = ∠BEA = 90°
If CD and BE are two lines then ∠CDA and ∠BEA form corresponding angles
∵ The corresponding angles are equal
∴ CD ║ BE
When two lines are parallel and a transversal line falls on it then the alternate angles are equal
if DB is a transversal line then ∠1 and ∠3 will be the alternate angles and they will be equal
Therefore
∠1 = ∠3 (Proved)
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