In the adjacent figure
figure ABII QR LBAQ - 142°
and LABP = 100° Find i LAPB ii) LAQR (1) LQRP
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Answer
Step-by-step explanation:
Given ∆ABC ~ ∆QRP,
AB=18 cm , BC = 15 cm,
/* we know that,
The ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides */
Therefore
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