Question

in the adjacent figure find the distance in kilometre from sea to a Robi ​

Answer 1

Answer:

In ∆ABD,

Base = 9m

Height = 40m

Area of ∆ABD =1/2×base×height

= 1/2 ×9 × 40sq.m

= 180 sq.m

Area of ∆BCD =1/2×base×height

= 1/2 ×13 × 60sq.m

= 390 sq.m

Area of quadrilateral ABCD = Area of ∆ABD + Area of ∆BCD

=

180sq.m+390sq.m

= 570 sq.m

Answer 2

Answer:

Answer:

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∆ABD,

Base = 9m

Height = 40m

Area of ∆ABD =1/2×base×height

= 1/2 ×9 × 40sq.m

= 180 sq.m

Area of ∆BCD =1/2×base×height

= 1/2 ×13 × 60sq.m

= 390 sq.m

Area of quadrilateral ABCD = Area of ∆ABD + Area of ∆BCD

=180sq.m+390sq.m

= 570 sq.m

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