Question

In the adjacent figure, find the refractive index of denser medium if refractive index of rarer medium

is 1?​

Answer 1

Follows are the solution to the given question:

Explanation:

Given:

$\mu_2=1\\\\\sin 90^{\circ}=1\\\\\sin 60^{\circ}=\frac{\sqrt{3}}{2}\\\\\mu_1=?$

Its refracted ray squeezes mostly on the surface again when refractive index would be a crucial case. Reflection will lead to a little rise in the angle of incidence.

$\to \mu_1 \times \sin(i) =\mu_2 \times \sin(r)\\\\\to \mu_1 \times \sin(60) =\mu_2 \times \sin(90)\\\\\to \mu_1 \times \frac{\sqrt{3}}{2} = 1 \times 1\\\\\to \mu_1 = \frac{1}{\frac{\sqrt{3}}{2}}\\\\\to \mu_1= \frac{2}{\sqrt{3}}$

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