Physics, asked by sofimd045, 4 months ago

In the adjacent Figure, find the refractive index of the rarer medium. (Sin 45°=1/√2)

Answers

Answered by ameen8086

3

Answer:

n12=nrnd

sin90sinθ=n3n2

sinRsini=n1n2

sini=sinr

sinRsinr=n1n2=sin90sinθc

cosrsinr=sinθc

cosr

tanr=sinθc

r=tan−1(sinθc)

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