Question

in the adjacent figure,if A=40°,CE||BA and <ECD=55°, find<ACB and <ABC ​

Answer 1

$\huge\bold\red{SOLUTION :-}$

Given

A = 40°

CE // BA

<ECD = 55°

we know that

Sum of angles of traingle = 180°

<A + <B + <C = 180°

40° + <B + <C = 180°

<B + <C = 180 - 40°

<B + <C = 140°

[ angle B = angle C ]

<B + <B = 140°

2B = 140°

B = 140° / 2

B = 70°

Answer 2

Answer:

Here,,,

Angle ACB=85°

And Angle ABC =55°

Because,,