. In the adjacent figure if x:y = 11:19. find ∠D C E .
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37
According to question
x : y = 11 : 19
Thus
x = 11 a
and y = 19 a
Ad is parallel to BE
So
Angle BDC = Angle ABD
y = 32
19 a = 32
So a = 32/19
Thus x = 11 * 32 / 19
x = 18.52
Since Angle DCE = Angle ADC
So Angle DCE = x + 32 = 18.52 + 32 = 50.32
x : y = 11 : 19
Thus
x = 11 a
and y = 19 a
Ad is parallel to BE
So
Angle BDC = Angle ABD
y = 32
19 a = 32
So a = 32/19
Thus x = 11 * 32 / 19
x = 18.52
Since Angle DCE = Angle ADC
So Angle DCE = x + 32 = 18.52 + 32 = 50.32
mskrishivarmap4gjbu:
you are wrong
Your solution is wrong...how can you take angle BDC=angle ABD??
no ur wrong the ans The ques should be AB⊥BD
Solving them
let x and y be 11a and 19a
then in ΔABD
11a+19a+90°=180° (angle sum property)
30a=90°
a=90°/30 = a=30°
∠x=33° (11a)
∠y=57°(19a)
as AB║BD
Then,∠ADC=∠DCE
∠DCE=65° (32+33)
:) Hope this helps!!!
Solving them
let x and y be 11a and 19a
then in ΔABD
11a+19a+90°=180° (angle sum property)
30a=90°
a=90°/30 = a=30°
∠x=33° (11a)
∠y=57°(19a)
as AB║BD
Then,∠ADC=∠DCE
∠DCE=65° (32+33)
:) Hope this helps!!!
AB is parallel to BC
oo nice
Answered by
11
How can you take angle A=90
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