in the adjacent figure its is given that AB=AC,<BAC=36,<ADB=45 and <AEC=40.find <ABC,<ACB,<DAB<EAC
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PLZ PROVIDE THE FIGURE...
as triangle ABC is an isoceles triangle LABC= LACB = (180 - 36)/2 = 22 (each)
and LABD = 180 - 22 = 58
so LDAB = 180-(58+45)
similarly LEAC = 180-(40+58) = 82
hope it helped !
as triangle ABC is an isoceles triangle LABC= LACB = (180 - 36)/2 = 22 (each)
and LABD = 180 - 22 = 58
so LDAB = 180-(58+45)
similarly LEAC = 180-(40+58) = 82
hope it helped !
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