Question

In the adjacent figure PO and RS are two mirrors Pe
placed parallel to cach other. An incident ray AB
strikes the mirror PO at B, the reflected ray moves
along the path BC and strikes the mirror RS at C
and again reflected back along CD. Prove that
AB || CD.
THint: Perpendiculars drawn to parallel lines are also parallel.)​

Answer 1

Answer:

good night sweet dreams friend

Answer 2

Answer:

Step-by-step explanation:

PQ || RS ⇒ BL || CM

[∵ BL || PQ and CM || RS]

Now, BL || CM and BC is a transversal.

∴ ∠LBC = ∠MCB …(1) [Alternate interior angles]

Since, angle of incidence = Angle of reflection

∠ABL = ∠LBC and ∠MCB = ∠MCD

⇒ ∠ABL = ∠MCD …(2) [By (1)]

Adding (1) and (2), we get

∠LBC + ∠ABL = ∠MCB + ∠MCD

⇒ ∠ABC = ∠BCD

i. e., a pair of alternate interior angles are equal.

∴ AB || CD.