Question

In the adjacent figure
Seg. AM perpendicular Seg. BC
Seg. BN perpendicular Seg. AC. If BC = 7 cm;
AM = 8√3 cm; AC =14√3 cm then BN = ?​

Answer 1

Answer:

Step-by-step explanation:

In ∆AMC and ∆BNC,

Angle A is equal to Angle B ,Angle C is common in both ∆ and both are right angle ∆ .

So we can use similar triangle theorem.

So AM/BN= MC/NC=AC/BC

Then ,AM/BN=AC/BC

(8√3)/(BN)= (14√3)/7

BN= (8√3 × 7)/(14√3)

BN=4