in the adjacent figure ,sides AC and AB of the right angled triangle are 2cm and root 3 respectively .find angle c
![in \: the \: adjacent \: figure \: sides \: ac \: and \: ab \: of \: the \: right \: angled \: triangle \: are \: 2cm \: and \: \sqrt{3 \: respectively.find \: c} in \: the \: adjacent \: figure \: sides \: ac \: and \: ab \: of \: the \: right \: angled \: triangle \: are \: 2cm \: and \: \sqrt{3 \: respectively.find \: c}](https://tex.z-dn.net/?f=in+%5C%3A+the+%5C%3A+adjacent+%5C%3A+figure+%5C%3A+sides++%5C%3A+ac+%5C%3A+and+%5C%3A+ab+%5C%3A+of+%5C%3A+the+%5C%3A+right+%5C%3A+angled+%5C%3A+triangle+%5C%3A+are+%5C%3A+2cm+%5C%3A+and+%5C%3A++%5Csqrt%7B3+%5C%3A+respectively.find+%5C%3A+c%7D+)
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Answer:
AC = 2cm
AB = sqrt(3) cm
B is the right triangle so AC is the hypotenuse, BC is base and AB is perpendicular so
sin C = P/H =
sin C = sin 60
C= 60 degree
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