In the adjacent figure,the bisectors of ∠A and ∠B meet in a point p. If ∠C = 100° and ∠D = 60° , find the measure of ∠APB. please solve this.
Answers
Answered by
7
As shown in the diagram, ABCD is a irregular quadrilateral.
One common property of all quadrilaterals is that the sum of all their angles equals 360^@
=> anglea+angleb+anglec+angled=360^@
Given that anglec=100^@, angled=60^@, and BP and AP bisects angleb and anglea, respectively,
=> anglea+angleb=360-(anglec+angled)=360-(100+60)=200^@
=> (anglea)/2+(angleb)/2=200/2=100^@
One common property of all quadrilaterals is that the sum of all their angles equals 360^@
=> anglea+angleb+anglec+angled=360^@
Given that anglec=100^@, angled=60^@, and BP and AP bisects angleb and anglea, respectively,
=> anglea+angleb=360-(anglec+angled)=360-(100+60)=200^@
=> (anglea)/2+(angleb)/2=200/2=100^@
Similar questions