Question

In the adjacent figure the height of a solid cyLinder is 10cm and diameter is 7cm .Two equal conical holes of radius 3cm and height 4cm are cut off as shown the figure. Find the volume of the remaining solid...​

Answer 1

Answer:

Ans- 309.57cm²

Step-by-step explanation:

Refer to the attachment :)

Answer 2

Answer:

694.6 $cm^{3}$

Step-by-step explanation:

Vol. of cylinder = π$r^{2}$h

                         = (22/7)*$(7/2)^{2}$*10

                         = 770 $cm^{3}$

Vol. of 2 cones = $\frac{1}{3}$$\pi$$r^{2}$h*2

                         = $\frac{1}{3}$*3.14*$3^{2}$*4*2

                         = 75.4 $cm^{3}$

Vol. of remaining solid = 770-75.4

                                      = 694.6 $cm^{3}$