Question

In the adjacent figure Triangle ABC and Triangle DBC are two triangle such that

Answer 1

Answer:

ANSWER

Given ; ΔABC and ΔDBC are two triangles such that AB=BD and AC=CD.

To show, ΔABC≅ΔDBC

proof;

in triangle DBM and triangle AMC,

AB=BC (Given)

AC=CD (Givne)

BC=BC ( Common )

Therefore, by SSS criterion of congruency, triangle ABC is congruent to triangle DBC.