in the adjacent figure triangle ABC D is the midpoint of BC DE is perpendicuar to AB,DF Perpendicular to AC and DE=BC show that triangle BED is congruent to triangle CFD
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hey mate here is your answer
Step-by-step explanation:
you know what, i think the figure is of another question........
but then i will try my best to answer your question...........
it is given that D is the midpoint of BC
:. BD=CD ................. (1)
but DE=BC is not possible .......
check the question once again ... edit it then i will answer it
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don't know fyfjovushgijfig
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