Question

In the adjacent figure triangleABC, D is the midpoint of BC.
DE | AB, DF | AC and DE=DF. Show that triangle BED is congruent to triangle CFD.


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Answer 1

Answer:

ANSWER

From △BED and △CFD

BD=CD  (D is a midpoit of BC)

DE=DF  (Given)

∠DEB=∠DFC   (DE⊥AB and DF⊥AC)

Thus,

△BED≅△CFD   (By RHS)