in the adjacent figure two blocks of masses 8kg ,6kg are placed on a horizontal smooth surface find the acceleration of each blocks and contact force between the blocks also find the given by the horizontal surface on each block
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Answer:
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Explanation:
The acceleration of each block is same.
a=(8+6)kg70N=5m/s2
Contact force is equal to
F=ma
F=(6×5)N=30N
Force exerted by the horizontal surface is equal to sum of weight and the vertical force on the body.
Force on first body
N1=(8×10+30)N=110N
N2=(6×10+20)N=80N
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