Question

in the adjacent figure two congruent circles at T. if OP=4.5cm then find QR​

Answer 1

Answer:

Hope it helps

Step-by-step explanation:

Given: In the figure below, two equal circles touch at T and QP = 4.5 cm

Given: In the figure below, two equal circles touch at T and QP = 4.5 cmTo find: The measure of QR

Given: In the figure below, two equal circles touch at T and QP = 4.5 cmTo find: The measure of QRThe two tangents drawn from an external point to a circle are equal in length.

Given: In the figure below, two equal circles touch at T and QP = 4.5 cmTo find: The measure of QRThe two tangents drawn from an external point to a circle are equal in length.Hence, we have

Given: In the figure below, two equal circles touch at T and QP = 4.5 cmTo find: The measure of QRThe two tangents drawn from an external point to a circle are equal in length.Hence, we haveQP = PT

Given: In the figure below, two equal circles touch at T and QP = 4.5 cmTo find: The measure of QRThe two tangents drawn from an external point to a circle are equal in length.Hence, we haveQP = PTPR = PT

Given: In the figure below, two equal circles touch at T and QP = 4.5 cmTo find: The measure of QRThe two tangents drawn from an external point to a circle are equal in length.Hence, we haveQP = PTPR = PTOn equating the L.H.S. of the two above equations, we get

Given: In the figure below, two equal circles touch at T and QP = 4.5 cmTo find: The measure of QRThe two tangents drawn from an external point to a circle are equal in length.Hence, we haveQP = PTPR = PTOn equating the L.H.S. of the two above equations, we getQP = PR

Given: In the figure below, two equal circles touch at T and QP = 4.5 cmTo find: The measure of QRThe two tangents drawn from an external point to a circle are equal in length.Hence, we haveQP = PTPR = PTOn equating the L.H.S. of the two above equations, we getQP = PRAccording to the given information, we have QP = 4.5 cm

Given: In the figure below, two equal circles touch at T and QP = 4.5 cmTo find: The measure of QRThe two tangents drawn from an external point to a circle are equal in length.Hence, we haveQP = PTPR = PTOn equating the L.H.S. of the two above equations, we getQP = PRAccording to the given information, we have QP = 4.5 cmHence, we get PR = 4.5 cm

Given: In the figure below, two equal circles touch at T and QP = 4.5 cmTo find: The measure of QRThe two tangents drawn from an external point to a circle are equal in length.Hence, we haveQP = PTPR = PTOn equating the L.H.S. of the two above equations, we getQP = PRAccording to the given information, we have QP = 4.5 cmHence, we get PR = 4.5 cmFrom the above figure, we can write

Given: In the figure below, two equal circles touch at T and QP = 4.5 cmTo find: The measure of QRThe two tangents drawn from an external point to a circle are equal in length.Hence, we haveQP = PTPR = PTOn equating the L.H.S. of the two above equations, we getQP = PRAccording to the given information, we have QP = 4.5 cmHence, we get PR = 4.5 cmFrom the above figure, we can writeQR = QP + PR

Given: In the figure below, two equal circles touch at T and QP = 4.5 cmTo find: The measure of QRThe two tangents drawn from an external point to a circle are equal in length.Hence, we haveQP = PTPR = PTOn equating the L.H.S. of the two above equations, we getQP = PRAccording to the given information, we have QP = 4.5 cmHence, we get PR = 4.5 cmFrom the above figure, we can writeQR = QP + PRQR = 4.5 + 4.5

Given: In the figure below, two equal circles touch at T and QP = 4.5 cmTo find: The measure of QRThe two tangents drawn from an external point to a circle are equal in length.Hence, we haveQP = PTPR = PTOn equating the L.H.S. of the two above equations, we getQP = PRAccording to the given information, we have QP = 4.5 cmHence, we get PR = 4.5 cmFrom the above figure, we can writeQR = QP + PRQR = 4.5 + 4.5QR = 9 cm

Given: In the figure below, two equal circles touch at T and QP = 4.5 cmTo find: The measure of QRThe two tangents drawn from an external point to a circle are equal in length.Hence, we haveQP = PTPR = PTOn equating the L.H.S. of the two above equations, we getQP = PRAccording to the given information, we have QP = 4.5 cmHence, we get PR = 4.5 cmFrom the above figure, we can writeQR = QP + PRQR = 4.5 + 4.5QR = 9 cmIn this way, we find that the measure of QR is 9 cm.