in the adjacent figures ABis parallel to CD and CD is parents to EF nad x:y=7:5,find Z value
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Consider △ADB and △EDF,
∠ADB=∠EDF [ Vertical angles ]
∠ABD=∠FED [ Alternate angles ]
∠BAD=∠EFD [ Alternate angles ]
∴ △ADB∼△EDF [ By ASA criterion ]
⇒ DEBD=FEAB
⇒ y4=106
⇒ 6y=40
⇒ y=640=320
⇒ y=6.67cm
Similarly, △ADE∼△CDE [ AA criterion ]
⇒ BEDE=BADC
⇒ 10.676.67=6x
⇒ x=6×10.676.67
⇒ x=3.75cm
∴ The values of x and
6.67cm.
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