Question

in the adjoinig figure,angle AOB=50° and angel BOC=COD.
a. angel BOC
b. angel COE ​

Answer 1

Answer:

A) 65

B) 115

Step-by-step explanation:

a) angel BOC + COD + AOB = 180

Let take angle BOC = AOB = X

X + X + 50 = 180

2X = 130

X = 65

b) angle COE + COB = 180

let angle COE = X

X + 65 = 180

X = 115

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Answer 2

Answer:

the answer is very easy.

as we know that angle BOC=COD we can say both the angles are x.

Step-by-step explanation:

so now,

angle BOC+angle COD+angle BOA=180 degrees(angles on a straight line are supplementary or the sum of angles on a straight line is 180 degrees).

as I had said angle BOC and COD are x so,

x+x+50=180 degrees

2x+50=180 degrees

2x=180-50 degrees

x=130/2

x=65 degrees

so angle BOC is 65 degrees.

now if u observe then u will see that BE is also a straight line.

So,

angle BOC+angle COD+angle DOE=180 degrees(angles on a straight line are supplementary or the sum of angles on a straight line is 180 degrees)

we got the value of both BOC and COD which is 65 degrees so now we can find the angle DOE.

let's name angle DOE as y.

65+65+y=180 degrees

y=180-130

y=50 degrees

now angle COE=angle COD +angleDOE

therefore angles COE=65+50

COE=105 degrees

Hope u get the sum.

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