Question

In the adjoining diagram angle p = 90° , PS is perpendicular to QS , OS = 6cm , PS = 8cm and PR = 24cm. Find : a) sin angle QPS b) tan angle RPS. ​

Answer 1

Answer:

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Step-by-step explanation:

$Given that:</p><p>QP=8cm,PR=6cm and SR=3cm</p><p>(I) In △PQR and △SPR</p><p>∠PRQ=∠SRP (Common angle)</p><p>∠QPR=∠PSR (Given that)</p><p>∠PQR=∠PSR (Properties of triangle )</p><p>∴△PQR∼△SPR (By AAA)</p><p>(II) </p><p>SP</p><p>PQ</p><p> </p><p> = </p><p>PR</p><p>QR</p><p> </p><p> = </p><p>SR</p><p>PR</p><p> </p><p> (Properties of similar triangles)</p><p>⇒ </p><p>SP</p><p>8cm</p><p> </p><p> = </p><p>3cm</p><p>6cm</p><p> </p><p> </p><p>⇒SP=4cm and </p><p>⇒ </p><p>6cm</p><p>QR</p><p> </p><p> = </p><p>3cm</p><p>6cm</p><p> </p><p> </p><p>⇒QR=12cm</p><p>(III) </p><p>ar(△SPR)</p><p>ar(△PQR)</p><p> </p><p> = </p><p>SP </p><p>2</p><p> </p><p>PQ </p><p>2</p><p> </p><p> </p><p> = </p><p>4 </p><p>2</p><p> </p><p>8 </p><p>2</p><p> </p><p> </p><p> =4$

Answer 2

Answer:

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