In the adjoining diagram attached ABCD is a rectangle with AE=EF=FB. what is the ratio of triangle CEF and that of rectangle
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Area of triangle Δ CEF = area of Δ CEB - area of Δ CFB
= 1/2 EB * BC - 1/2 FB * BC
= 1/2 (2 AB/3) * BC - 1/2 (AB/3) * BC = 1/6 * AB * BC
area of rectangle = AB * BC
Ratio = 1/6
= 1/2 EB * BC - 1/2 FB * BC
= 1/2 (2 AB/3) * BC - 1/2 (AB/3) * BC = 1/6 * AB * BC
area of rectangle = AB * BC
Ratio = 1/6
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