Question

In the adjoining electrical circuit the internal resistance of the cell is5 ohm and its e.m.f. is 29 volt. Find
(i) total resistance of the circuit,
(ii) current in the circuit,
(iii) potential difference between points A and B.
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Answer 1

Explanation:

Refer image .1

Given :- Let the current How in 3Ω is i, and 6Ω is i1=1ampere

i1+i2=I

VA−VB=i1×3Ω=i2×6

⇒1×3=i2×6

2i=21ampere

Hence I=i1+i2=1+0.5=1.5ampere

Req=2+3+63×6=2+93×6=4Ω

equivalent circuit

Refer image .2

From KVL

1req=v

v=1.5×4

=6volt