Question

in the adjoining fegure ap -4 cm,bq-6cm and cr-5cm find perimeter of abc​

Answer 1

Answer:

The perimeter of ∆ABC is 30 cm

Step-by-step explanation:

Here, in the above triangle

Seg AB is the tangent at point P,

Seg AC is the tangent at point R

and

Seg BC is the tangent at point Q

Also,

BY USING TANGENT SEGMENT THEOREM :

TANGENT SEGMENTS DRAWN FROM AN EXTERNAL POINT TO A CIRCLE ARE CONGRUENT.

:. AP congruent AR

:. AP = 4 cm then AR = 4 cm

:. BQ congruent BP

:. BQ = 6 cm then BP = 6 cm

:. RC congruent QC

:. RC = 5 cm then QC = 5 cm

then,

:. AB = AP + BP ---(Points A,P & B are collinear)

:. AB = 10 cm

:. AC = AR + RC ---(Points A,R & C are collinear)

:. AC = 9 cm

:. BC = BQ + QC ---(Points B,Q & C are collinear)

:. BC = 11 cm

:. Perimeter of triangle = AB + BC + AC

:. Perimeter of triangle = 10 + 11 + 9

:. Perimeter of triangle = 30 cm

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