in the adjoining fig o is center of circle PA is the tangent is the circle at point A if l(PA) = 5cm. then find m OAP
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The diameter of the circle =30cm.
∴ Its radius =OA=230cm=15cm.
∠AOP=90o since a tangent to a circle makes 90o angle with the radius joining the centre and the point of contact of the tangent to the circle.
So ΔAOP is a right one with hypotenuse as OP.
(i) PA=OP2−OA2=392−152cm=36. cm.
(ii) OP=AP2+OA2=202+152cm=25 cm.
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