Question

In the adjoining fig . pT is a
tangent to acircle whose
centre is O, If op=25cm
T = rem Find the length
of Tangent PT.

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Answer 1

Answer:

Step-by-step explanation:

Hello Shreya,

Join O, T. Hence OT ⊥ PT Therefore, PTO is a right angled triangle In the given figure, PT = 8 cm, PA = 4 cm By Pythagoras theorem, we have OP2 = OT2 + PT2 (PA + OA)2 = OT2 + PT2 PA2 + 2 x PA x OA + OA2 = OT2 + PT2 PA2 + 2 x PA x OT + OT2 = OT2 + PT2 [Since OA = OT = radii] 42 + 2 x 4 x OT = 82 16 + 8 x OT = 64 8 x OT = 48 Therefore, OT = 6 cm Thus radius of the circle is 6 cm.