In the adjoining figure 10.21, lines DA, BE, CF intersectato. If AOB = 50°, COD = 60°, find 1, 2, 3 and 4 Fig. 10.21
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1 = 70 °
2 = 50°
3 = 70°
4 = 60°
Step-by-step explanation:
angle COD = angle 4
(vertically opposite angles are equal)
angle 4 = 60°
angle AOF = angle 2
(vertically opposite anglesare equal)
angle 2 = 50°
Angle sum property
angle 2 + angle 3 + angle 4 = 180°
50° + angle 3 + 60° = 180°
angle 3 = 70°
angle 1 = angle 3 (vertically oppsiticlas are equal)
angle 1 = 70°
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