Question

In the adjoining figure​

Answer 1

Answer:

1)-

angle BMD =45°

angleAEM=67.5°

angleCAD=42°

Answer 2

Step-by-step explanation:

angleABC=180-(angleACB+angleCAB)

=180-(48+90)

=180-138

=42°

angleCBM=42/2( bisected)

=21°

i) angleBMD=180-(90+21) [ASP of a triangle]

=180-111

=69°

ii) angleAEM=180-(90+21) [ASP of a triangle]

=180-111

=69°

angleCDA=180-90(linear pair)

=90°

iii)angleCAD=180-(90+48) [ASP of a triangle]

=180-138

=42°

Hope it is clear...

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