Question

In the adjoining figure 2QPR = 62° and ZPRQ = 64°. If OQ and OR and bisectors of ZPQR and [1] PRQ respectively, then ZOQR and ZQOR :-
a) 121", 20°
b) 27°, 121°
c) 20", 80°
d) 26°, 124​

Answer 1

Answer:

option a is correct answer

Answer 2

Answer:

b) 27°, 121°

Step-by-step explanation:

in triangle PQR

62°+64°+angle PQR= 180° (angle sum property)

126° + angle PQR= 180°

angle PQR= 180°-126°

angle PQR=54°

now,

it is given that OQ is the bisector of PQR

=) OQR= 1/2 PQR

=) OQR= 1/2 54°

=) OQR= 27°

similarly

ORQ= 1/2 PRQ

ORQ= 1/2 64°

ORQ= 32°

now, by angle sum property

OQR+ORQ+QOR=180^

27°+32°+QOR=180°

59+QOR=180°

QOR= 180°-59°

QOR= 121°