in the adjoining figure ,,,.....
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Hi!!!!
As AD is perpendicular to BC,
∆ABD and ∆ADC are right angled triangles.
By py.theorm,
AB^2=BD^2 + AD^2 in ∆ABD
AC^2=AD^2 + DC^2 in ∆ADC
By subtracting both the equations we get. :
AB^2 - AC^2 = BD^2 -DC^2
Hence AB^2 - BD^2 =AC^2-DC^2
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