Question

in the adjoining figure a b parallel CD find the value of x​

Answer 1

Answer:

if AB//FD and AF ìs transversal

angle EFC =105 degrees(corresponding angles)

x=25+105=130 degrees(exterior angle property)

Answer 2

x=130 degree

Step-by-step explanation:

Given : Angle A=105 degree

Angle E= 25 degree

Construction: Extend the CD  to AE and intersect AE at point F.

AB is parallel to CD and AE is transversal

Angle CFE=Angle A=105 degree (Corresponding angles)

In triangle CFE

Angle CFE+angle CEF+angle FCE=180 degrees

By triangle angles sum property

Substitute the values

$105+25+\angle FCE=180$

$130+\angle FCE=180$

$\angle FCE=180-130=50^{\circ}$

Angle FCE+angle DCE=180 degree (Linear pair sum)

Substitute the values

$50+\angle DCE=180$

$\angle DCE=180-50=130^{\circ}$

Hence, the angle x=Angle DCEE=130 degree

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