Question

In the adjoining figure, a circle with center O of radius 7 cm is​

Answer 1

Answer:

Since tangent at a point on a circle is perpendicular to the radius through the point. Therefore, OP is perpendicular to PQ.

In right triangle OPQ, we have

OQ

2

=OP

2

+PQ

2

⇒OQ

2

=7

2

+24

2

⇒OQ

2

=49+576

⇒OQ

2

=625

⇒OQ=25 cm.