Question

In the adjoining figure, a circle with centre O
is inscribed in a quadrilateral ABCD. If
angle AOB
= 125°, then angle
COD is equal to​

Answer 1

Step-by-step explanation:

180°-125°=55° this is vertically opposite angles

Answer 2

we know that, the opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the center of the circle. So, we have

∠AOB + ∠COD = 180°

125° + ∠COD = 180°

∠COD=55