Question

In the adjoining figure a die is thrown it lands in the interior of the circle. What is the probability that the die will land in the shaded region??

Answer 1

Since the circle has divided into mainly two parts that is a square having a diagonal and rest partd of the circle are shaded.

So total no. of favourable outcomes =2

And no. of trial=1

So probability (die will land in shaded) region=1/2

Answer 2

Answer:

10.28/28.28

Step-by-step explanation:

ABCD is a square. its diagonal is 6m

by pythagoras theorem,

   AB²+BC²=AC²

    X²+X²=6²

           2X²=36

                 X=√18

area of square = X²

                        =[√18]²

                         =18

area of circle=πr²

                     =22/7*3*3

                      =28.28

probability=area of shaded region/area of circle

                 =28.28-18/28.28

                =10.28/28.28

                =0.3635...

                =